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A uniform circular disc of radius `r` is placed on a rough horizontal surface and given a linear velocity `v_(0)` and angular velocity `omega_(0)` as shown. The disc comes to rest after moving some distance to the right. It follows that A. r/2B. rC. 3r/2D. 2 |
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Answer» Correct Answer - A `mV_(0)R-(mR^(2))/2. omega_(0)=0 rArr (V_(0))/(omega_(0))=R/2` |
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