1.

A uniform electric field is present in the positive x - direction. If the intensity of the field is `5 NC^-1` then find the potential difference `(V_B - V_A)` between two points A (0 m, 2 m) and B (5 m, 3 m).

Answer» we know potential difference between points A and B in uniform electric field is `V_B - V_A = - vec(E) . vecA B`. Here we are given `vec(E) = 5 hat(i) (Vm^-1)` and
`vec A B = (5 - 0) hat(i) + (3 - 2) hat(j) (m)`
Hence, `V_B - V_A = -(5 hat(i)).(5 hat(i) + hat(j))= - 25 V`.


Discussion

No Comment Found

Related InterviewSolutions