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A uniform flag pole of length `L `and mass `M` in pivoted on the ground with a frictionless hinge. The flag pole makes an angle `theta` with the horizontal. The moment of inertia of the flag pole about one end is `(1//3) ML^(2)`. If starts falling from the position shown in figure, the linear acceleration of the free end of the flag pole-labeled `P` - would be. .A. `(2/3)gcostheta`B. `(2/3)g`C. `g`D. `(3/2)gcostheta` |
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Answer» Correct Answer - D `(MgL)/2costheta=(ML^(2))/3alpha` `alpha=3/2(gcostheta)/L` `a=alphaL=3/2gcostheta` |
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