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A uniform force of (3i+j) newton acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i+k) meter to position(4 i +3j-k) meter. The work done by the force on the particle is(1) 13 J(2) 15 J(3) 9J(4) 6J |
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Answer» Let the particle be displaced from position A to B under the action of the given force thenAB=B-A (taking(0,0,0) as origin) =2i+3j-2kNow,work done on the particle =(force). (displacement) =(3i+j).(2i+3j-2k)=9 |
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