1.

A uniform metre rule of weight 10gf is pivoted at its 0 mark.(i) what moment of force depresses the rule?(ii) how it can be made horizontal by applying least force?

Answer»

1-Moment of force =magnitude of force X perpendicular distance of the line of action of force from the axis of rotation= 50cm X 10gf = 500 gf cm (ans)2-To apply the least force we obviously have to make the perpendicular distance highest. Hence, the least force should be applied at 100cm mark.Thus, by principle of moments500 gf cm = 100cm X force=> force = 5 gfThe force should be 5 gf upwards at the 100 xm mark



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