a uniform metre rule placed on a fulcrum at its midpoint and having a

1.	a uniform metre rule placed on a fulcrum at its midpoint and having a weight 50 gf at 10 cm mark and a weight of 40 gf at 90 cm, how can the scale be brought in equilibrium by adding 50 gf
Answer» ANSWER: Anticlockwise MOMENT = 40 × (50 – 10) = 1600 dyne cm Clockwise moment = 20 × (90 – 50) = 800 dyne cm. Since anticlockwise moment is greater than the clockwise moment. So, for equilibrium suspend the 40gf away from 50 cm mark. Then, 1600 = 800 + 40x ⇒ 40x = 800 The 40 g has to be suspended at (50 + 20) = 70 cm. Explanation: Please mark me as brainliest

a uniform metre rule placed on a fulcrum at its midpoint and having a weight 50 gf at 10 cm mark and a weight of 40 gf at 90 cm, how can the scale be brought in equilibrium by adding 50 gf

Answer»

Anticlockwise MOMENT = 40 × (50 – 10)

= 1600 dyne cm

Clockwise moment = 20 × (90 – 50)

= 800 dyne cm.

Since anticlockwise moment is greater than the clockwise moment. So, for equilibrium suspend the 40gf away from 50 cm mark.

Then, 1600 = 800 + 40x

⇒ 40x = 800

The 40 g has to be suspended at (50 + 20) = 70 cm.

Explanation:

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a uniform metre rule placed on a fulcrum at its midpoint and having a weight 50 gf at 10 cm mark and a weight of 40 gf at 90 cm, how can the scale be brought in equilibrium by adding 50 gf

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