A uniform solid sphere of radius `r` is rolling on a smooth horizontal surface with velocity `v` and angular velocity `omega = (v=omega r)`. The sphere collides with a sharp edge on the wall as shown in figure. The coefficient of friction between the sphere and the edge `mu=1//5`. Just after the collision the angular velocity of the sphere becomes equal to zero. The linear velocity of the surface just after the collision is equal to A. `v`B. `v/5`C. `(3v)/5`D. `v/6`

A uniform solid sphere of radius `r` is rolling on a smooth horizontal

1.	A uniform solid sphere of radius `r` is rolling on a smooth horizontal surface with velocity `v` and angular velocity `omega = (v=omega r)`. The sphere collides with a sharp edge on the wall as shown in figure. The coefficient of friction between the sphere and the edge `mu=1//5`. Just after the collision the angular velocity of the sphere becomes equal to zero. The linear velocity of the surface just after the collision is equal to A. `v`B. `v/5`C. `(3v)/5`D. `v/6`
Answer» Correct Answer - A Impulse provided by the edge in the horizontal direction `-intNdt =-mV^(1)-(MV)....(1)` Friction impulse in the vertical direction `muRintNdt=2/5 mR^(2)(V/R)....(2)` from eq(1) and (2) we get `int Ndt=2mV` and `V^(1)=V`

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