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A vector along the bisector of angle between the vectors `vecb` and `vecc` is,A. `(2+sqrt(3))hati + (1-sqrt(3))hatj+(2+sqrt(3))hatk`B. `(2+sqrt(3))hati+(1-sqrt(3))hatj-(2+sqrt(3))hatk`C. `(2+sqrt(3))hati-(1-sqrt(3))hatj-(2+sqrt(3))hatk`D. `(2+sqrt(3))hati-(1-sqrt(3))hatj+(2+sqrt(3))hatk` |
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Answer» Correct Answer - A Vector along the bisectors is `(hati-hatj+hatk)/sqrt(3) + (4hati+2hatj+4hatk)/6` `1/3(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk` `therefore` Vectors is `(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk` |
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