1.

A vector along the bisector of angle between the vectors `vecb` and `vecc` is,A. `(2+sqrt(3))hati + (1-sqrt(3))hatj+(2+sqrt(3))hatk`B. `(2+sqrt(3))hati+(1-sqrt(3))hatj-(2+sqrt(3))hatk`C. `(2+sqrt(3))hati-(1-sqrt(3))hatj-(2+sqrt(3))hatk`D. `(2+sqrt(3))hati-(1-sqrt(3))hatj+(2+sqrt(3))hatk`

Answer» Correct Answer - A
Vector along the bisectors is
`(hati-hatj+hatk)/sqrt(3) + (4hati+2hatj+4hatk)/6`
`1/3(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk`
`therefore` Vectors is `(2+sqrt(3))hati+(1-sqrt(3))hatj+(2+sqrt(3))hatk`


Discussion

No Comment Found

Related InterviewSolutions