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`veca=2veci+vecj+veck`, `vecb=b_(1)hati+b_(2)hatj+b_(3)hatk`, `veca xx vecb=5hati+2hatj-12hatk, veca.vecb=11`, then `b_(1)+b_(2)+b_(3)=`A. 3B. 5C. 7D. 9 |
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Answer» Correct Answer - B `vecb= ((vecaxxvecb)xx veca+(veca.vecb)veca)/(|veca|^(2))` `=6hati-3hatj+2hatk` `rArr vecb_(1)+vecb_(2)+vecb_(3)=6-3+2=5` |
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