A vector of magnitude 10along the normal to the curve `3x^2+8x y+2y^2-3=0`at its point `P(1,0)`can be`6 hat i+8 hat j`b. `-8 hat i+3 hat j`c. `6 hat i-8 hat j`d. `8 hat i+6 hat j`A. `6hati + 8hatj`B. `-8 hati + 3hatj`C. `6hati - 8 hatj`D. `8 hati + 6 hatj`

A vector of magnitude 10along the normal to the curve `3x^2+8x y+2y^2-

1.	A vector of magnitude 10along the normal to the curve `3x^2+8x y+2y^2-3=0`at its point `P(1,0)`can be`6 hat i+8 hat j`b. `-8 hat i+3 hat j`c. `6 hat i-8 hat j`d. `8 hat i+6 hat j`A. `6hati + 8hatj`B. `-8 hati + 3hatj`C. `6hati - 8 hatj`D. `8 hati + 6 hatj`
Answer» Correct Answer - a Differentiate the curve `6x + 8 ( xy_(1) + y) + 4 yy_(1) =0` `m_(T)at (1,0) is 6 + 8 (y_(1)(0)) =0` ` y_(1) (0) = -3/4` `m_(N)= 4/3` Unit vector =` +- (3hati + 4hatj) / 5` Again normal of magnitude ` 10 =+- (6hati + 8hatj)`

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A vector of magnitude 10along the normal to the curve `3x^2+8x y+2y^2-3=0`at its point `P(1,0)`can be`6 hat i+8 hat j`b. `-8 hat i+3 hat j`c. `6 hat i-8 hat j`d. `8 hat i+6 hat j`A. `6hati + 8hatj`B. `-8 hati + 3hatj`C. `6hati - 8 hatj`D. `8 hati + 6 hatj`

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