If `vecr and vecs` are non-zero constant vectors and the scalar b is chosen such that `|vecr+bvecs|` is minimum, then the value of `|bvecs|^(2)+|vecr+bvecs|^(2)` is equal toA. `2|vecr|^(2)`B. `|vecr|^(2)//2`C. `3|vecr|^(2)`D. `|vecr|^(2)`

If `vecr and vecs` are non-zero constant vectors and the scalar b is c

1.	If `vecr and vecs` are non-zero constant vectors and the scalar b is chosen such that `\|vecr+bvecs\|` is minimum, then the value of `\|bvecs\|^(2)+\|vecr+bvecs\|^(2)` is equal toA. `2\|vecr\|^(2)`B. `\|vecr\|^(2)//2`C. `3\|vecr\|^(2)`D. `\|vecr\|^(2)`
Answer» Correct Answer - b For minimum value `\|vecr+ bvecs\|=0` Let `vecr and vecs` are anti - parallel so `bvecs =- vecr` `\|bvecs\|^(2) + \|vecr + bvecs\|^(2) = \|-vecr\|^(2) + \|vecr-vecr\|^(2) = \|vecr\|^(2) `

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