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If `veca=a_(1)hati+a_(2)hatj+a_(3)hatk, vecb= b_(1)hati+b_(2)hatj + b_(3)hatk, vecc=c_(1)hati+c_(2)hatj+c_(3)hatk and [3veca+vecb 3vecb+vecc 3vecc + veca] =lambda|{:(veca.hati,veca.hatj,veca.hatk),(vecb.hati,veca.hatj,hatb.hatk),(vecc.hati,vecc.hatj,vecc.hatk):}| " then find the value of " lambda/4` |
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Answer» Correct Answer - 7 `veca=a_(1)hati=a_(2)hatj +a_(3)hatk` `vecb=b_(1)hati+b_(2)hatj+b_(3)hatk` `vecc = c_(1)hati +c_(2)hatj +c_(3)hatk` L.H.S = ` [3veca +vecb 3vecb+vecc 3vecc +veca]` `[3veca 3vecb 3vecc] + [vecb vecc veca]` `3^(3)[veca vecb vecc] + [veca vecb vecc]` `28 [veca vecb vecc]` |
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