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A vector `vecd` is equally inclined to three vectors `veca=hati-hatj+hatk,vecb=2hati+hatj and vecc=3hatj-2hatk.` Let `vecx,vecy and vecz` be three vectors in the plane of `veca,vecb;vecb,vec;vecc,veca,` respectively. ThenA. `vecx.vecd=-1`B. `vecy.vecd= 1`C. vecz.vecd=0`D. vecr.vecd=0, " where " vecr=lambda vecx + mu vecy +deltavecz` |
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Answer» Correct Answer - c.d Since `[veca vecb vecc] =0, veca, vecb and vecc` are coplanar vectors. Further, since, `vecd` is equally inclined to `veca ,vecb and vecc,` `vecd.veca =vecd.vecb = vecd.vecc=0` `vecd.vecx =vecd.vecy = vecd.vecz =0` `vecd.vecr =0` |
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