A vector `vecd` is equally inclined to three vectors `veca=hati-hatj+hatk,vecb=2hati+hatj and vecc=3hatj-2hatk.` Let `vecx,vecy and vecz` be three vectors in the plane of `veca,vecb;vecb,vec;vecc,veca,` respectively. ThenA. `vecz.vecd =0`B. `vecx.vecd=1`C. `vecy.vecd= 32`D. `vecr.vecd= 0 , " where " vecr= lambdavecx+ muvecy+ gammavecz`

A vector `vecd` is equally inclined to three vectors `veca=hati-hatj+h

1.	A vector `vecd` is equally inclined to three vectors `veca=hati-hatj+hatk,vecb=2hati+hatj and vecc=3hatj-2hatk.` Let `vecx,vecy and vecz` be three vectors in the plane of `veca,vecb;vecb,vec;vecc,veca,` respectively. ThenA. `vecz.vecd =0`B. `vecx.vecd=1`C. `vecy.vecd= 32`D. `vecr.vecd= 0 , " where " vecr= lambdavecx+ muvecy+ gammavecz`
Answer» Correct Answer - a,d ` veca =hati -hatj +hatk` ` vecb = 2hati +hatj` `and vecc = 3hatj -2hatk` since, `[veca vecb vecc]= \|{:(1,-1,1),(2,1,0),(0,3,-2):}\|=0` therefore, `veca,vecb and vecc` are coplanar vectors, furthere, sicne `vecd` is equally inclined to `veca, vecb anv vecc` we have `vecd. veca=vecd.vecb=vecd.vecc=0` ` vecd.vecx=vecd.vecy =vecd.vecz=0`, `vecd.vecr =0`

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