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A vessel contains equal mass of CO2 and N2O . The mole fraction of CO2 is.. |
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Answer» Answer:33.3 Explanation:INITIAL partial pressures of CO and CO 2 are 3 atm and 2 atm respectively. 2CO(g)⇋CO 2 (g)+C(s) To reach EQUILIBRIUM, 2x atm of CO reacts to FORM x atm of CO 2
The equilibrium partial pressures of CO and CO 2 are 3−2x atm and 2+x atm respectively. Total equilibrium PRESSURE is (3−2x)+(2+x)=5−x atm. But it is equal to 4.5 atm. 4.5=5−x x=5−4.5 x=0.5 p CO :p CO 2
=(3−2x):(2+x)=(3−2(0.5)):(2+1(0.5))=2:2.5=4:5 K p = P CO 2
P CO 2
K p = 2 2
2.5
K p =0.625atm −1
The DISSOCIATION of CO = 3 2x = 3 2(0.5) =0.333 The % dissociation of CO =100×0.333=33.3 |
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