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A vessel contains water up to a height of 6 cm. Taking the density of water 1000 kg m-3 and acceleration due to gravity 10 ms-2 calculate the pressure at the base of vessel |
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Answer» Pressure =ρgh where ρ=density of water g=acceleration DUE to gravity P=10 3 ×9.8×1.5=1.47×10 4 Nm 2
UPTHRUST = FORCE EXERTED = Pressure \times Area ⇒Upthrust=1.47×10 4 Nm 2 ×100×10 −4 m=147N |
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