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A weightless thread can bear tension upto `3.7 kg` wt A stone of mass `500g` is tied to it and revolves in a verticle circle of radius `4m` What will be the maximum angular velocity of the stone if `g = 10 m//s^(2)` . |
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Answer» Correct Answer - `4rad//s` . Here, `T_(max) = 3.7kg wt = 37 N` `m = 500 g = 0.5kg` `r = 4 m, omega = ? g = 10m//s^(2)` As `T _(max) = (m upsilon^(2))/(r)+ mg` `:. (m upsilon^(2))/(r) = T_(max) - mg = 37 - 0.5 xx 10 =32` `upsilon^(2) =(32r)/(m) =(32 xx 4)/(0.5) = 256` `upsilon = sqrt(256) = 16m//s` ` omega = (upsilon)/(r) = (16)/(4) = 4rad//s` . |
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