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A well is dug 20 m deep and it has a diameter of 7 m. The earth which is so dug out is spread out on a rectangular plot 22 m long and 14 m broad. What is the height of the platform so formed? |
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Answer» Given, Depth of well = 20 m Diameter of well = 7 m Radius of well = \(\frac{7}{2}\) m Dimension of rectangular field = 22 m × 14 m so, Amount of earth dug out from well = πr2h = \(\frac{22}{7}\) x \(\frac{7}{2}\) x \(\frac{7}{2}\) x 20 = 770 m3 when this earth is spread on rectangular field: Then height of platform formed on rectangular field = \(\frac{volume\,of\, earth\,dug\,out}{area\,of\,rectangular\,out}\) = \(\frac{770}{22\times 14}\) = 2.5 m |
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