1.

A wire 2m in length suspended vertically stretches by 1mm when a mass of 20 kg is attached to the lower end. The elastic potential energy gained by wire is ………… (use `g= 10 m//s^2)`

Answer» 0.1 J [ Elastic pot. Energy,`U = (1)/(2) F Delta l = (1)/(2) xx (20 xx 10) xx (10^(-3) = 0.1 J)].`


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