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A wire having a linear mass density `5.0xx10^(3) kg//m` is stretched between two rigid supports with tension of 450 N. The wire resonates at a frequency of `420 Hz`. The next higher frequency at which the same wire resonates is` 480 N`. The length of the wire isA. `2.0 m`B. `2.1 m`C. `2.5 m`D. `3 m` |
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Answer» Correct Answer - B Two consecutive frequencies are 420 Hz and 480 Hz. So the fundamental frequency will be `60 Hz`. `60=(1)/(2xxl)sqrt((450)/(5xx10^-3))impliesl=2.1m` Hence (b). |
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