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A wire is in the form of a square of side 18m. It is bent in the form of a rectangle, whose length and breadth are in theratio `3: 1.`The area of the rectangle is`81 m^2 `(b) 243 `m^2`(c) 144 `m^2`(d) 324 `m^2`A. `81m^(2)`B. `243m^(2)`C. `144m^(2)`D. `324m^(2)` |
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Answer» Correct Answer - B Total length of wire = `"Perimeter of square"=4xx18=72 m` Let the length, breadth of rectangle be 3x and x, respectively. `therefore"Perimeter of rectangle "=2(3x+x)=72m` `4x=36` x = 9 `rArr"Length"=3xx9=27m` Breadth = 9 m `"Area of rectangle"=27xx9=243m^(2)` |
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