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A wire is under a tension of 32N and length between the two bridges in 1m. If the length of the sample wire is 10m and its mass is 2 g, then the fundamental frequency of the wire will beA. 400HzB. 200HzC. 100HzD. 800Hz |
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Answer» Correct Answer - B `n=(1)/(2l) sqrt(T/m) = (1)/(2xx1) sqrt((32)/(2xx10^(-4))` `=1/2xx4xx10^2` `=400/2 = 200` |
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