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A Wire of given material having length 7' and area of cross-section 'A' has aresistance of 8Ω. What would be the resistance of another wire of the same materialhaving length and area of cross- section 2A.2 |
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Answer» Resistance = p l/a [ p is constant]For first wire length = l and area of croos section = aResistance = p l/a = 8 ohm [given] For second wire length = l/2 and area of cross section = 2aResistance = p (l/2) / 2a = p l/4a = p l/a * 1/4 [p l/a = 8 ohm] = 8*1/4 = 2 ohm The resistance of second wire = 2 ohm |
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