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A wire of length 1m and diameter 0.2 mm has resistance of 10 ohm. Calculate the resistivity of the wire |
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Answer» Explanation: here , it is Given that: l=1m ,d=0.2mm=>r=0.1mm and R=10 OHM by using the FORMULA, R= p౹/ A = p౹/ πr² therefore, p= Rπr²/l = 10× 3.14×( 0.1× 10 -³)² = 10× 3.14× 0.1×0.1× 10 to the power -6 = 0.314× 10 to the power-6 = 3.14× 10 to the power-7 ohm- m hence, the RESISTIVITY of the conductor is 3.14× 10 to the power-7 ohm- m Click to let OTHERS know, how hel |
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