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                                    A wire of resistance 16 ohms is elongated double its length. Find the new resistance. | 
                            
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Answer»  As we know that ;Resistance = Resistivity*length/areaHere we note that the resistance is directly proportional to length and inversely proportional to area of cross section ....Now a/c to question,;Length of wire is double then area is reduced to half...NowNew resistance = resistivity*2length/area/2New resistance =(resistivity*length/area)*4New resistance = 4resistance  | 
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