1.

A woman throws an object of mass `500g` with a speed of `25 ms^(-1)` . (a) What is the impulse imparted to the object ? (b) If the object hits a wall and rebounds with half the original speed what is the change in momentum of the object ?

Answer» Here, ` m = 500 g = (1)/(2) kg , u = 25 ms^(-1) `
(a) Impulse imparted = change in momentum = initial momentum given ` m u = (1)/(2) xx25 = 12.5 Ns `
(b) On rebounding force the wall ` upsilon = -(1)/(2) xx 25 = - 12.5 m//s `
Change in momentum ` = m (upsilon- u ) = (1)/(2) (-12.5- 25) = - 18.75 kg ms^(-1)` .


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