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A wooden ball of density D is immersed in water of density d to a depth h//2 below the surface of water and then relased. To what height will the ball jump out of water ?

Answer» Correct Answer - `((d)/(D) - 1) (h)/(2)`
Let V be the volume of the ball Effective upward thrust on ball = V dg - V D g Upward ac celeration of ball, `a = (V d g- VD g)/(VD) = ((d - D)/(D))g`
Velocity of the ball on reaching the surface `upsilon = sqrt(2 ah//2) = sqrt(ah)` If the ball rises through height H outside the liquid, the then `upsilon = sqrt(2 g H)`
`:. sqrt(ah) = sqrt(2 g H)`
or `H = (ah)/(2g) = ((d -D)/(D)) (gh)/(2g) = ((d)/(D) - 1) (h)/(2)`


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