Answer:

11th

Physics

Work, Energy and Power

Collisions in Two Dimensions

A WOODEN block of mass 10 g...

PHYSICS

A wooden block of mass 10 g is dropped from the top of a tower 100 m high. Simultaneously, a bullet of mass 10 g is fixed from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will the block rise above the top of tower before it starts falling? (g=10m/s2)

A

75 m

B

85 m

C

80 m

D

10 m

HARD

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ANSWER

Given :     m=10 gm  =0.01kg

Let the block and the bullet collides at point A after time t.

For block :              x=0+21gt2

x=21×10×t2           ⟹x=5t2            ............(1)

For bullet :              100−x=ut−21gt2

100−x=(100)t−21×10×t2           ⟹100−x=100t−5t2            ............(2)

Solving (1) and (2),  we get          t=1 s          and            x=5 m

Let velocities of bullet and block just before COLLISION be  VB  and  VW  respectively.

∴     vb=u−gt

v

Explanation:

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