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a11. A 4 kg block is suspended by two strings AC and BCas shown in figure. Then tension in the string BC is-ILIILII30°: 45°4kg |
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Answer» Assume left string has tension = T1 and right string has tension = T2. the force balance equation along y axis is T1cos30+T2cos45 = 4*10 N => T1√3/2 +T2/√2 = 40 and along x axis , it is T1sin30 = T2/√2 => T1 = √2(T2)..... putting this in above equation. we get √3(T2)/√2 +(T2)/√2 = 40 => T2*(√3+1)/√2 = 40 => T2 = 40√2/(√3+1) N |
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