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ABC is a triangle such that `sin(2A+B)=sin(C-A)=-sin(B+2C)=1/2`. If A,B, and C are in AP. then the value of A,B and C are.. |
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Answer» Here, `sin(B+2C) = -1/2` As it is a negative value, `(B+2C)` is greater than `180^@` .`:. B+2C = 180+30=> B+2C = 210^@->(1)` `sin(C-A) = 1/2=> C-A = 30^@->(2)` `sin(2A+B) = 1/2 => 2A+B = 180-30=>2A+B = 150^@->(3)` As, `A,B and C` are in AP. `:. A+C = 2B->(4)` From (1), `2B+4C = 420^@` `=>A+5C = 420^@->(5)` Adding (2) and (5), `C-A+A+5C = 420+30=> 6C = 450=> C = 75^@` `A = 75-30 = 45^@` `B = (45+75)/2 = 60^@` |
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