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ABC is a triangle with ∠BAC = 90°, then what is the value of sin2A + sin2B + sin2C?1). 12). 23). 34). 4 |
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Answer» sin2A + sin2B + sin2C = sin290° + sin2(90° – C) + sin2C (? In a RIGHT angled triangle SUM of other two angles = 90°) = 1 + cos2C + sin2C (? sin2θ + cos2θ = 1) = 1 + 1 = 2 ∴ sin2A + sin2B + sin2C = 2 |
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