1.

ABC is a triangle with ∠BAC = 90°, then what is the value of sin2A + sin2B + sin2C?1). 12). 23). 34). 4

Answer»

sin2A + sin2B + sin2C

= sin290° + sin2(90° – C) + sin2C

(? In a RIGHT angled triangle SUM of other two angles = 90°)

= 1 + cos2C + sin2C

(? sin2θ + cos2θ = 1)

= 1 + 1 = 2

∴ sin2A + sin2B + sin2C = 2


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