1.

Abc is an equilateral triangle charges +q are placed at each corners the electric intensity at o will be

Answer»

Answer:

0

Explanation:

As per the diagram (in the ATTACHMENT) ;

Keeping in mind that \\\tt E_{1} = E_{2} = E_{3} = \dfrac{1}{4 \pi \epsilon_{\circ}} \dfrac{q}{r^2}

Net electric field by \\\tt E_{1} and \\\tt E_{2}  is given by:

\\\tt E_{1+2 } =\sqrt{E_{1}^{2} + E_{2}^{2} + 2E_{1} E_{2} \cos\theta} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}\cos120^{\circ}} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}(\dfrac{-1}{2}) } \\\\\\\tt = \sqrt{2E_{1}^{2} - E_{1}^{2} } \\= E_{1}

Now,

Net FORCE between \\\tt E_{1+2} and \\\tt E_{3} are PERPENDICULAR to each other they cancel each other out making net electric field 0.


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