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Abc is an equilateral triangle charges +q are placed at each corners the electric intensity at o will be |
| Answer» <html><body><p><strong>Answer:</strong></p><p><a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a></p><p></p><p><strong>Explanation:</strong></p><p>As per the diagram (in the <a href="https://interviewquestions.tuteehub.com/tag/attachment-385146" style="font-weight:bold;" target="_blank" title="Click to know more about ATTACHMENT">ATTACHMENT</a>) ;</p><p></p><p>Keeping in mind that <img align="absmiddle" alt="\\\tt E_{1} = E_{2} = E_{3} = \dfrac{1}{4 \pi \epsilon_{\circ}} \dfrac{q}{r^2}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B1%7D%20%3D%20E_%7B2%7D%20%3D%20E_%7B3%7D%20%3D%20%5Cdfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon_%7B%5Ccirc%7D%7D%20%5Cdfrac%7Bq%7D%7Br%5E2%7D" title="\\\tt E_{1} = E_{2} = E_{3} = \dfrac{1}{4 \pi \epsilon_{\circ}} \dfrac{q}{r^2}"/></p><p></p><p>Net electric field by <img align="absmiddle" alt="\\\tt E_{1}" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B1%7D" title="\\\tt E_{1}"/> and <img align="absmiddle" alt="\\\tt E_{2}" class="latex-formula" id="TexFormula3" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B2%7D" title="\\\tt E_{2}"/> is given by:</p><p></p><p><img align="absmiddle" alt="\\\tt E_{1+2 } =\sqrt{E_{1}^{2} + E_{2}^{2} + 2E_{1} E_{2} \cos\theta} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}\cos120^{\circ}} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}(\dfrac{-1}{2}) } \\\\\\\tt = \sqrt{2E_{1}^{2} - E_{1}^{2} } \\= E_{1}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B1%2B2%20%7D%20%3D%5Csqrt%7BE_%7B1%7D%5E%7B2%7D%20%2B%20E_%7B2%7D%5E%7B2%7D%20%20%2B%202E_%7B1%7D%20E_%7B2%7D%20%5Ccos%5Ctheta%7D%20%5C%5C%5C%5C%5Ctt%20%3D%20%5Csqrt%7B2E_%7B1%7D%5E%7B2%7D%20%20%2B%202E_%7B1%7D%5E%7B2%7D%5Ccos120%5E%7B%5Ccirc%7D%7D%20%5C%5C%5C%5C%5Ctt%20%3D%20%5Csqrt%7B2E_%7B1%7D%5E%7B2%7D%20%20%2B%202E_%7B1%7D%5E%7B2%7D%28%5Cdfrac%7B-1%7D%7B2%7D%29%20%7D%20%5C%5C%5C%5C%5C%5C%5Ctt%20%3D%20%5Csqrt%7B2E_%7B1%7D%5E%7B2%7D%20%20-%20E_%7B1%7D%5E%7B2%7D%20%7D%20%5C%5C%3D%20E_%7B1%7D" title="\\\tt E_{1+2 } =\sqrt{E_{1}^{2} + E_{2}^{2} + 2E_{1} E_{2} \cos\theta} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}\cos120^{\circ}} \\\\\tt = \sqrt{2E_{1}^{2} + 2E_{1}^{2}(\dfrac{-1}{2}) } \\\\\\\tt = \sqrt{2E_{1}^{2} - E_{1}^{2} } \\= E_{1}"/></p><p></p><p>Now,</p><p>Net <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> between <img align="absmiddle" alt="\\\tt E_{1+2}" class="latex-formula" id="TexFormula5" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B1%2B2%7D" title="\\\tt E_{1+2}"/> and <img align="absmiddle" alt="\\\tt E_{3}" class="latex-formula" id="TexFormula6" src="https://tex.z-dn.net/?f=%5C%5C%5Ctt%20E_%7B3%7D" title="\\\tt E_{3}"/> are <a href="https://interviewquestions.tuteehub.com/tag/perpendicular-598789" style="font-weight:bold;" target="_blank" title="Click to know more about PERPENDICULAR">PERPENDICULAR</a> to each other they cancel each other out making net electric field 0.</p><p></p><p></p><p></p></body></html> | |