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ABCD is a parallelogram and O is the point of intersection of its diagonals. If `ar(triangle AOD)= 4cm^2` find `ar(triangle AOB)` |
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Answer» ABCD is a parallelogram Diagonal AC and BD bisects each other. Mid point of AC=Midpoint of BD O is bisect BD in two part. AO is themedian of`/_ABD` Median divides the area of triangle `/_ABD` in two equals parts. area of`/_AOD= area of`/_AOB`` A=area of`/_AOB` `area(/_ADB)=4cm^2`. |
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