1.

ABCD is a parallelogram and O is the point of intersection of its diagonals. If `ar(triangle AOD)= 4cm^2` find `ar(triangle AOB)`

Answer» ABCD is a parallelogram
Diagonal AC and BD bisects each other.
Mid point of AC=Midpoint of BD
O is bisect BD in two part.
AO is themedian of`/_ABD`
Median divides the area of triangle `/_ABD` in two equals parts.
area of`/_AOD= area of`/_AOB``
A=area of`/_AOB`
`area(/_ADB)=4cm^2`.


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