InterviewSolution
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About how many times more intense will the normal ear perceiver a sound of `10 ^(6) W //m^(2)` than one of `10^(9) W//m^(2)` ? |
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Answer» `L_(1) = 10 log_(10) ((I_(1))/(I_(o)))` = `10 log_(10) ((10^(-6))/(10^(-12))) = 60 dB` `L_(2) = 10 log_(10) ((I_(2))/(I_(o)))` = `10 log_(10) ((10^(-9))/(10^(-12))) = 30 dB` `L_(2) = 2l_(2)` |
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