1.

accelerates a stationaryparticle of mass 15 g through a displacement of 2.50 mFind the work done and the average power delivered.5. A constant force of 250 N

Answer»

Work done = Force x displacement.

= 2.50 x 2.50

= 6.25 Joule.

Avg. Power = Force x velocity...................(1)

From the work energy theorem,

2.50 x 2.50 = 0.5 * 15/1000 * v^2

12.5 * 1000/15 = v^2

v = root(12500/15) = > 28.86 m/s.

put v in eq. (1) we get,

Avg. Power = 2.50 x 28.86 => 721.15 Watt.



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