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accelerates a stationaryparticle of mass 15 g through a displacement of 2.50 mFind the work done and the average power delivered.5. A constant force of 250 N |
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Answer» Work done = Force x displacement. = 2.50 x 2.50 = 6.25 Joule. Avg. Power = Force x velocity...................(1) From the work energy theorem, 2.50 x 2.50 = 0.5 * 15/1000 * v^2 12.5 * 1000/15 = v^2 v = root(12500/15) = > 28.86 m/s. put v in eq. (1) we get, Avg. Power = 2.50 x 28.86 => 721.15 Watt. |
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