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According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent voltage source is?(a) V^‘=(V1G1+V2G2+⋯.+VnGn)(b) V^‘=((V1G1+V2G2+⋯.+VnGn))/((1/G1+1/G2+⋯1/Gn))(c) V^‘=((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn)(d) V^‘=((V1/G1+V2/G2+⋯.+Vn/Gn))/( G1+G2+⋯Gn)I have been asked this question in an online quiz.This interesting question is from Millman’s Theorem topic in chapter Useful Theorems in Circuit Analysis of Network Theory |
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Answer» CORRECT OPTION is (c) V^‘=((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn) Explanation: The VALUE of EQUIVALENT voltage source is V^‘= ((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn). |
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