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According to Millman’s Theorem, if there are n voltage sources with n internal resistances respectively, are in parallel, then the value of equivalent voltage source is?(a) V^‘=(V1G1+V2G2+⋯.+VnGn)(b) V^‘=((V1G1+V2G2+⋯.+VnGn))/((1/G1+1/G2+⋯1/Gn))(c) V^‘=((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn)(d) V^‘=((V1/G1+V2/G2+⋯.+Vn/Gn))/( G1+G2+⋯Gn)I have been asked this question in an online quiz.This interesting question is from Millman’s Theorem topic in chapter Useful Theorems in Circuit Analysis of Network Theory

Answer» CORRECT OPTION is (c) V^‘=((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn)

Explanation: The VALUE of EQUIVALENT voltage source is V^‘= ((V1G1+V2G2+⋯.+VnGn))/(G1+G2+⋯Gn).


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