InterviewSolution
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InterviewSolution
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Acetoc acid `CH_(3)COOH` can form a dimer `(CH_(3)COOH)_(2)` in the gas phase. The dimer is held togther by two `H-`bonds with a total strength of `60.0 kJ per` mole of dimer If at `25^(@)C`, the equilibrium constant for the dimerisation is `1.3 xx 10^(3)`, calculate `DeltaS^(Theta)` for the reaction `2CH_(3)COOH (g) hArr (CH_(3)COOH)_(2)(g)` |
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Answer» `DeltaG^(Theta) =- 2.303 RT log_(10)k` `=- 2.303 xx 8.314 xx 298 log (1.3 xx10^(3))` `=- 17767.688 J = - 17.767 kJ` `DeltaG^(Theta) = DeltaH^(Theta) - T DeltaS^(Theta)` `- 17.767 =- 60.0 - 298 xx DeltaS^(Theta)` `DeltaS^(Theta) = (-60.0+17.767)/(298) =- 0.141 kJ` |
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