InterviewSolution
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Add the following rational numbers:(i)\(\, \frac{3}{4}\, and\, \frac{-5}{8}\)(ii) \(\frac{5}{-9}\, and\, \frac{7}{3}\)(iii) \(-3\, and\, \frac{3}{5}\)(iv) \(\frac{-7}{27}\, and\, \frac{11}{18}\)(v) \(\frac{31}{-4}\, and\, \frac{-5}{8}\)(vi) \(\frac{5}{36}\, and\, \frac{-7}{12}\)(vii) \(\frac{-5}{16}\, and\, \frac{7}{24}\)(viii) \(\frac{7}{-18}\, and\, \frac{8}{27}\) |
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Answer» (i) The denominator of given rational numbers are 4 and 8 respectively The L.C.M. of 4 and 8 is 8 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{3\times 2}{4\times 2} = \frac{6}{8}\) and \(\frac{-5}{8}\) Therefore, \(\frac{6}{8}\, -\, \frac{5}{8}\, =\, \frac{6-5}{8}\) \(= \frac{1}{8}\) (ii) The denominator of given rational numbers are 9 and 3 respectively The L.C.M of 9 and 3 is 9 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{-5\times 1}{9\times 1} = \frac{-5}{9} \) and \(\frac{7\times 3}{3\times 3} = \frac{21}{9}\) Therefore, \(\frac{-5}{9} + \frac{21}{9} = \frac{-5+21}{9}\) \(= \frac{16}{9}\) (iii) The denominator of given rational numbers are 1 and 5 respectively The L.C.M of 1 and 5 is 5 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{-3\times 5}{1\times 5} = \frac{-3\times 5}{5}\) and \(\frac{3}{5}\) Therefore, \(\frac{-15}{5} + \frac{3}{5} = \frac{3-15}{5}\) \(= \frac{-12}{5}\) (iv) The denominator of given rational numbers are 27 and 18 respectively The L.C.M of 27 and 18 is 54 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{-7}{27} = \frac{-7\times 2}{27\times 2}\) = \(\frac{-14}{54}\) And, \(\frac{11}{18} = \frac{11\times 3}{18\times 3}\) = \(\frac{33}{54}\) Therefore, \((\frac{-7\times2}{27\times 2}) + \frac{33}{54}\) = \(\frac{33}{54} - \frac{14}{54}\) = \(\frac{33-14}{54}\) = \(\frac{19}{54}\) (v) The denominator of given rational numbers are -4 and 8 respectively The L.C.M of -4 and 8 is 8 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{31}{4} = \frac{31\times 2}{-4\times 2}\) = \(\frac{-62}{8}\) And, \(\frac{5}{8}\) Therefore, \((\frac{-31\times 2}{4\times 2}) + \frac{-5}{8}\) = \(\frac{-62}{8} - \frac{5}{8}\) = \(\frac{-67}{8}\) (vi) The denominator of given rational numbers are 36 and 12 respectively The L.C.M of 36 and 12 is 36 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{-7\times3}{12\times 3} = \frac{-21}{36}\) And, \(\frac{5}{36}\) Therefore, \(\frac{5}{36} - \frac{21}{36}\) = \(\frac{-16}{36}\) = \(\frac{-4}{9}\) (vii) The denominator of given rational numbers are 16 and 24 respectively The L.C.M of 16 and 24 is 48 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{-5}{16} = \frac{-5\times 3}{16\times 3}\) = \(\frac{-15}{48}\) And, \(\frac{7}{24} = \frac{7\times 2}{24\times 2}\) = \(\frac{14}{48}\) Therefore, \(\frac{-5}{16} + \frac{7}{24}\) = \(\frac{-15}{48} + \frac{14}{48}\) = \(\frac{-1}{48}\) (viii) The denominator of given rational numbers are -4 and 8 respectively The L.C.M of 18 and 27 is 54 Now, we rewrite the given rational numbers into forms in which both of them have the same denominator \(\frac{7}{-18} = \frac{7\times 3}{-18\times 3}\) = \(\frac{-21}{54}\) And, \(\frac{8\times 2}{27\times 2}\) = \(\frac{16}{54}\) Therefore, \(\frac{-21}{54} + \frac{16}{54}\) = \(\frac{16-21}{54}\) = \(\frac{-5}{54}\) |
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