

InterviewSolution
Saved Bookmarks
1. |
Find the value of:(i) \((\frac{5}{8})^{-1}\)(ii) \((\frac{-4}{9})^{-1}\)(iii) \((-7)^{-1}\)(iv) \((\frac{1}{-3})^{-1}\) |
Answer» Let there be a rational number \(\frac{a}{b}\) then \((\frac{a}{b})^{-1}\) = \(\frac{b}{a}\) Therefore, (i) \((\frac{5}{8})^{-1}=\frac{8}{5}\) (ii) \((\frac{-4}{9})^{-1}=\frac{9}{-4} =\frac{9\times-1}{-4\times-1}=\frac{-9}{4}\) (iii) \((-7)^{-1}=(\frac{-7}{1})^{-1}=\frac{1}{-7}= \frac{1\times-1}{-7\times-1}=\frac{-1}{7}\) (iv) \((\frac{1}{-3})^{-1}=\frac{-3}{1}=-3\) |
|