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Adding powdered Pb and Fe to a solution containing 1.0 M each of `Pb^(2+)` and `Fe^(2+)` ions would result into the formation of:A. More of Pb and `Fe^(2+)` ionsB. More of Fe and `Pb^(2+)` ionsC. More of Fe and PbD. More of `Fe^(2+)` and `Pb^(2+)` ions |
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Answer» Correct Answer - A `E_(Pb^(2+)//Pb)^(@)gtE_(Fe^(2+)//Fe)^(@)` so, Fe will oxidise and `Pb^(2+)` will reduce. |
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