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After digitization process a digital image with M rows and N columns have to be positive and for the number, L, max gray levels i.e. an integer power of 2 for each pixel. Then, the number b, of bits required to store a digitized image is:(a) b=M*N*k(b) b=M*N*L(c) b=M*L*k(d) b=L*N*kI have been asked this question in a job interview.My enquiry is from Representing Digital Images topic in section Digital Image Fundamentals of Digital Image Processing

Answer»

The correct answer is (a) b=M*N*K

Easiest EXPLANATION: In digital image of M rows and N columns and L max gray LEVELS an integer power of 2 for each pixel. The number, b, of bits REQUIRED to store a digitized image is: b=M*N*k.



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