InterviewSolution
Saved Bookmarks
| 1. |
ALLEA ring of mass 10 kg and diameter 0.4 meter is 6rotating about its geometrical axis at 1200 rotationsper minute. Its moment of inertia and angularmomentum will be respectively-(1) 0.4 kg-m2 and 50.28 J-S(2) 0.4 kg-m2 and 0.4 J-s(3) 50.28 kg-m2 and 0.4 J-S2 |
|
Answer» Radius of ring , R = 0.4/2 = 0.2 m mass of ring , M = 10 Kg (i) moment of inertia , I = MR² I = 10 × (0.2)² = 10 × 0.04 = 0.4 Kg.m² (ii) angular momentum , L = Iω∵ ω = 2πν , here I = 0.4 Kg.m² and ν = 1200rpm = 1200/60 r/s ∴ L = 0.4 × 2π × 1200/60 = 50.24 ≈ 50 Kgm²/s |
|