An A.P. consists of 60 terms. If the first and the last terms be 7 and

1.	An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.
Answer» Given, an A.P of 60 terms And, a = 7 and a₆₀ = 125 We know that a_n = a + (n – 1)d ⇒ a₆₀ = 7 + (60 – 1)d = 125 7 + 59d = 125 59d = 118 d = 2 So, the 32^nd term is given by a₃₂ = 7 + (32 -1)2 = 7 + 62 = 69 ⇒ a₃₂ = 69

An A.P. consists of 60 terms. If the first and the last terms be 7 and 125 respectively, find 32nd term.

Answer»

Given, an A.P of 60 terms

And, a = 7 and a₆₀ = 125

We know that a_n = a + (n – 1)d

⇒ a₆₀ = 7 + (60 – 1)d = 125

7 + 59d = 125

59d = 118

d = 2

So, the 32^nd term is given by

a₃₂ = 7 + (32 -1)2 = 7 + 62 = 69

⇒ a₃₂ = 69