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An aircraft executes a horizontal loop at a speed of `720 km h^(-1)` , with its wings banked at `15^(@)` What is the radiue of the loop ?A. 14.8kmB. 14.8mC. 29.6kmD. 29.6m |
Answer» Correct Answer - A Here, `v=720 km h^(-1)=720xx(5)/(18)ms^(-1)=200 ms^(-1)` `theta=15^(@), g=10ms^(-2) "As" tan theta=(v^(2))/(rg)` `therefore r=(v^(2))/(tan thetag)=(200 ms^(-1))^(2)/(tan 15^(@)xx10ms^(-2))=14815m=14.8km` |
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