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An aircraft travelling at 600 km/h accelerates steadily at 10 km/h per second. Taking the speed of sound as1100 km/h at the aircraft's altitude, how long will it take to reach the 'sound barrier' ? |
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Answer» Final velocity, v = 1100 km/h= 1100 × 5/18 = 305.55m/sInitial velocity,u= 600 km/h= 600 × 5/18 = 166.66m/sAcceleration = 10 km/hper second = 10 × 5/18 = 2.77m/s2Time taken by body,v =u + att= (v -u)/at = (305.55 -166.66 )/2.77t = 50.14 sect≃50 sec |
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