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An astronaut is approacing the moon. He sends a radio wave of frequency `5 xx 10^(9) Hz` towards the moon. The frequency of the radio echo received by him has a frequency `9 xx 10^(4) Hz` more than that of real frequency. The relative velocity of the rocket with respect to the moon isA. 1.35 km/sB. 2.70 km/sC. 4.05 km/sD. 5.40 km/s |
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Answer» Correct Answer - D `n = 5 xx 10^(9)Hz, Delta n = 9 xx 10^(4) Hz` `c = 3 xx 10^(8) m//s, v = ?` `(Delta n)/(n) = (v)/(c)` `:. v = (Delta n xx c)/(n)` `= (9 xx 10^(4) xx 3 xx 10^(8))/(5 xx 10^(9))` `v = 5.4 xx 10^(3) m//s = 5.4 km//s` |
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