1.

An electric dipole is placed at angle of 60° toan electric seild of intensity 10° NYC. Iteyaeriences å torque o 8 13 pop nm. calculatecharge on dipole eth dipole dength is 2 cm(8x10 3 C)

Answer»

The formula for torque when an electric dipole I'd placed in electric field is

Torque = PE Sin tetha

P = 2r(q) [ Dipole moment]

E = 1000000N/C

8√3 = 2 × 10^-2 (q) 10^5 Sin 60°

q = 8√3 ×2 / 2 × 10^3√3

q = 8 × 10^-3 C



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