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An electric field of 30 N/C exists along the negative x-axis in space. Calculate the potential difference V-Vwhere the points A and B are given by,(a) A = (0,0): B = (0,2m)(b) A = (4m, 2m): B = (6m, 5m) |
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Answer» (a) zero because both point lie on equipotential surface(b) 30×(6-4) =60V |
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