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An electric heater supplies heat to a system at a rate of `100W`. If sustem performs work at a rate `74 Joul es` per second, at what rate is the internal energy increasing? |
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Answer» Heat is supplied to the system at a rate of 100 W. `therefore"Heat supplied", Q = 100 J//s` The system performs at a rate of 75 `J//s.` `therefore"Work done", W = 75 J//s` From the first law of thermodynamics, we have: `Q=U+W` Where, U=Internal energy `thereforeU=Q-W` `= 100 – 75` `= 25 J//s` `= 25 W` Therefore, the internal energy of the given electric heater increases at a rate of 25 W. |
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